Roku Developer Program

[jbrave]

here's one idea for starters:

function validate(xmltag as string, obj as object) as boolean
	xmlcheck=obj.getnamedelements(xmltag) 
		return xmlcheck<>invalid and xmlcheck.count() >0
end function

[TheEndless]

What about a generic GetChildElementText() function?

Function GetChildElementText( parentElement As Object, childName As String, defaultValue = "" As String ) As String
    child = parentElement.GetNamedElements( childName )
    If child <> invalid and child.Count() > 0 Then
        Return child.GetText()
    Else
        Return defaultValue
    End If
End Function

Then your code can be simplified to:

m.TrackURL = GetChildElementText( track, "stream-url" )
m.TrackGenre = GetChildElementText( track, "genre" )
m.TrackDescription = GetChildElementText( track, "description" )
m.TrackCreated = GetChildElementText( track, "created-at" )
m.WaveformURL = GetChildElementText( track, "waveform-url" )
m.ArtworkURL = GetChildElementText( track, "artwork-url" )

[jbrave]

Ok. What about a generic function that will do this for an unknown set of tags? So if I have m.xmltracklist, I could do something like:

taglist=extractTagList(m.xmltracklist)
for each tag in taglist
getChildElement(taglist.tag)
next

Since m.xmltracklist is an RoXMLElement, which appears to contain a list of roXMLElements:

BrightScript Debugger> ?type(m.xmltracklist)
roXMLElement
BrightScript Debugger> ?m.xmltracklist.GetChildElements()
<ROT:roXMLElement>
<ROT:roXMLElement>
<ROT:roXMLElement>
<ROT:roXMLElement>

which I assume represent each tag and its content, is there a way that you know of to get a list of all the tags in any given set of XML?

- Joel

[TheEndless]

I think you just discovered it yourself 😉
If you do a recursive loop through the roXMLElement.GetChildElements(), you can walk the entire document. GetName() should return the name of the element.

[jbrave]

sort of:

v=track.GetChildElements()

BrightScript Debugger> ?v.GetName()
Member function not found in BrightScript Component or interface.

BrightScript Debugger> ?v[1].GetName()
created-at
BrightScript Debugger> ?v[2].GetName()
user-id

Don't quite know what I would do a "for each" on... I can imagine doing: a

For i=1 to (v.count() -1)
? v
next

Any suggestions?

[TheEndless]

For Each node in xml.GetChildElements()
    print node.GetName()
Next

[jbrave]

So if I understand this correctly, "node" is just a placeholder for "item" or "element" of an array, it doesn't have any meaning with relationship to the actual names of the elements of the array?

- Joel

[TheEndless]

Correct. It's just a variable equal to the current child element in the loop.

[jbrave]

Ok, thanks for explaining that!

- Joel