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EnTerr
Roku Guru

RSG.unobserveField() - "nuclear option" or not?

I am confused by this text:
"ifSGNodeField" wrote:

unobserveField(name as String)
Removes the previously established connections between the subject node field identified by name and any callback functions or message ports.

Does this mean that calling node.unobserveField("fieldName") will remove from node.fieldName any and all observer "contracts" by any and all components/threads (hence "nuke" them) - or does this apply only to the observers from the current context?

As a reminder, multiple components/threads may have registered observer functions/ports over the same field. 
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TheEndless
Channel Surfer

Re: RSG.unobserveField() - "nuclear option" or not?

It only applies to the current context.  The same context in which observeField was called.
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EnTerr
Roku Guru

Re: RSG.unobserveField() - "nuclear option" or not?

"TheEndless" wrote:
It only applies to the current context.  The same context in which observeField was called.

So all observers (functions and ports) established from the current context (interpreter) will be stripped for the field - but the ones from another (e.g. next-door thread) over the same field will survive? 

PS. here is amusing thought... what happens if one calls observeField() multiple times in exactly the same context and params? I figure it will either (a) cause multiple consecutive firings of same event or (b) ... not.
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TheEndless
Channel Surfer

Re: RSG.unobserveField() - "nuclear option" or not?

"EnTerr" wrote:
So all observers (functions and ports) established from the current context (interpreter) will be stripped for the field - but the ones from another (e.g. next-door thread) over the same field will survive?

Correct.

"EnTerr" wrote:
PS. here is amusing thought... what happens if one calls observeField() multiple times in exactly the same context and params? I figure it will either (a) cause multiple consecutive firings of same event or (b) ... not.

a.

These questions are all easily tested, so to quote another helpful forum member.. have you tried it? 😉
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EnTerr
Roku Guru

Re: RSG.unobserveField() - "nuclear option" or not?

"TheEndless" wrote:
These questions are all easily tested, so to quote another helpful forum member.. have you tried it? 😉

Touché! 😄
Not quite... but touché, Sir - for digging these examples!

Here is what i mean by "not quite". There could be different standards on documentation - personally i would be satisfied by one that a "competent and reasonable developer" can read and use. By "reasonable" i mean "a hypothetical person in society who exercises average care, skill, and judgment in conduct" (see Reasonable Person Standard). And by "competent developer" i assume one that knows the difference between between a local and a global variable, between a value and a reference type... actually pretty high bar, comparatively to what we get in Roku world.

To which i posit, such competent&reasonable developer:

  • reading that Overhand is subclass of Group, will deduce children can be added

  • will expect 4k video plays like any other, in the absence of explicit disclaimer

  • will expect "any callback functions or message ports" for unobserveField() to mean the "nuclear option" (everywhere in the app)... and will be wrong on that, per your experiments

So this is an under-documented or wrongly-documented behavior that should be fixed - otherwise unobserveField() is useless, without it being codified whether it affects the other xml-components or not.
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TheEndless
Channel Surfer

Re: RSG.unobserveField() - "nuclear option" or not?

"EnTerr" wrote:
will expect "any callback functions or message ports" for unobserveField() to mean the "nuclear option", everywhere in the app... and will be wrong on that (per your experiments?)

If you consider that the caller of observeField() is the observer, then it stands to reason that that same caller would only be able to undo observations that it has initiated.
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EnTerr
Roku Guru

Re: RSG.unobserveField() - "nuclear option" or not?

"TheEndless" wrote:
"EnTerr" wrote:
will expect "any callback functions or message ports" for unobserveField() to mean the "nuclear option", everywhere in the app... and will be wrong on that (per your experiments?)

If you consider that the caller of observeField() is the observer, then it stands to reason that that same caller would only be able to undo observations that it has initiated.

No, it does not. I am example of a "competent and reasonable developer" who when reading "any callback functions or message ports" assumes that "ANY" means what it says (that is, EVERY/ALL). In fact, let me broaden that - why would a random reasonable person think otherwise?

I can guess why you think the way you do - you have been long enough around roWanda's tank. And i am only half-way there (i.e. level "suspicious") because of lesser exposure. But why do you expect J. Random Hacker to have your mind bends? 
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TheEndless
Channel Surfer

Re: RSG.unobserveField() - "nuclear option" or not?

"EnTerr" wrote:
why would a random reasonable person think otherwise?

Not debating that the documentation is a little ambiguous, but why would a "competent and reasonable developer" think that any component could randomly delete a different component's field observations?  I could understand the observee being able to remove multiple observers, but one observer deleting another doesn't make sense to me, especially when you consider that the observers generally aren't aware of each other's existence.
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EnTerr
Roku Guru

Re: RSG.unobserveField() - "nuclear option" or not?

"TheEndless" wrote:
... but why would a "competent and reasonable developer" think that any component could randomly delete a different component's field observations?  I could understand the observee being able to remove multiple observers, but one observer deleting another doesn't make sense to me, especially when you consider that the observers generally aren't aware of each other's existence.

Because

  1. A "reasonable person" when seeing unqualified "ANY", assumes it means what it says - removes any and all. Does it say "current caller's ..."? (It does not.)

  2. Components can already peek & poke at each other's Fields - intuitively they could meddle with observer functions too (there is no expectation of privacy)

  3. Notice you are muddling here the meaning of "observer" - observers are not objects but "pseudo-methods" (functions defined in XML file extending a class). Say observer  myClass::f1() was placed over anotherNode.FieldFoo. It is not such observer myClass::f1() that deletes itself - rather it could be (and likely is) another, unrelated function myClass::g2() that calls anotherNode.unobserveField() to remove "any" observer functions. 

  4. And what if (a function from) anotherNode wants to strip all observers from its very own FieldFoo? That is a business use too! It makes a good case for anotherNode.unobserveField("FieldFoo") being able to shake all "peeping Toms" off its own field.
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TheEndless
Channel Surfer

Re: RSG.unobserveField() - "nuclear option" or not?

Components in SceneGraph are isolated from each other, so while technically the "observer" is the function you register, that function has to be available in the same context as the code that's calling observeField().  Since that code is isolated to the component, I think it's fair to refer to the component as the observer.

Now, consider you have a ContentNode that provides the content for multiple grid components (grid1 and grid2).  Each grid component may want to register an observer on the ContentNode to monitor for any changes to the data, so it can update its UI.  If unobserveField() were nuclear, then grid1 would have no way unregistering its observer when its ContentNode (or visibility) changes without also unregistering grid2's observer.
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