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agmark
Visitor

Math Functions

I need to do some formatting of numbers and it seems Brightscript is fairly limited in math functions. Does anyone have a good solution for formatting numbers to 2 decimal places? I'm pulling in numbers from external sources and they come in unformatted. For example: 160 or 160.9 or 160.95 or 160.955 or -160 etc. I need a to format as 160.95 or -160.95. I'm sure I could come up with some hack to do it, but there's probably a better way than I'm coming up with.
TIA
Mark
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11 REPLIES 11
RokuMarkn
Visitor

Re: Math Functions

Something like this ought to work:

v = Int((value + .005) * 100)
units = int(v/100)
decimal = v mod 100
d = decimal.ToStr()
if d < 10 then d = "0" + d
formatted = units.ToStr() + "." + d

I just wrote this off the top of my head and haven't tested it.

--Mark
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agmark
Visitor

Re: Math Functions

ok, I added this:
Int(lp) = content.lprice
to deal with the type mismatch of my initial value, but I'm also getting a type mismatch on this line that I'm not sure about:
if d < 10 then d = "0" + d
Is it the type of "10" that's mismatched?
The code looks like:
Int(lp) = content.lprice
v = Int((lp + .005) * 100)
units = int(v/100)
decimal = v mod 100
d = decimal.ToStr()
if d < 10 then d = "0" + d
formatted = units.ToStr() + "." + d
print formatted
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RokuMarkn
Visitor

Re: Math Functions

That should be

if decimal < 10 then d = "0" + d


--Mark
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gonzotek
Visitor

Re: Math Functions

"agmark" wrote:
ok, I added this:
Int(lp) = content.lprice
to deal with the type mismatch of my initial value, but I'm also getting a type mismatch on this line that I'm not sure about:
if d < 10 then d = "0" + d
Is it the type of "10" that's mismatched?
The code looks like:
Int(lp) = content.lprice
v = Int((lp + .005) * 100)
units = int(v/100)
decimal = v mod 100
d = decimal.ToStr()
if d < 10 then d = "0" + d
formatted = units.ToStr() + "." + d
print formatted
The line immediately above the one that has the mismatch error sets the type of d to String. Since you still have the numerical decimal variable, try
if decimal < 10 then d = "0" + d
/edit Mark beat me to it 🙂
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agmark
Visitor

Re: Math Functions

Haha. Good eyes guys! Thanks for the quick help. I also had my initial value converted to an integer wrong.
Int(lp) = content.lprice
should be:
lp = content.lprice
lp = lp.ToInt()
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RokuMarkn
Visitor

Re: Math Functions

Hm, I don't understand that part. Why are you converting it to an integer? If you do that, the decimal part will always be .00

--Mark
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agmark
Visitor

Re: Math Functions

You're right. I'm getting a type mismatch and I thought that converting the inital string to an int would solve it, but as you say, now I'm getting zeros. How do I convert the initial value to something that this line can deal with?
v = Int((lp + .005) * 100)
My initial value from the xml parse is
content.lprice
assigned to lp so I could experiment with the value with:
lp = content.lprice
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RokuMarkn
Visitor

Re: Math Functions

You probably want ToFloat

lp = content.lprice.ToFloat()


--Mark
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agmark
Visitor

Re: Math Functions

Now that's something I hadn't even tried. It looks like it's working on positive numbers, but I'm getting a weird format for negatives. I'm not sure why, but a negative number is formatting like: -1.0-63 whereas a postive is correct like: 0.07. Any clue why?
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