Roku Developer Program

[dynamitemedia]

i want to use a for loop to get video files from a list.
example file list:

video-1.mp4
video-2.mp4
video-3.mp4
video-4.mp4

this works to get the "number" of the videos i want.

videoNum=0
for i=1 to 4
    videoNum = videoNum +1
   print "video number is"; videoNum
end for

but this only returns the "Number", so what do i need to do to add a number at the end of the video file?

i have tried adding a few different ways but i always get a type mismatch error.

arrays and loops confuse me so much at times, even in php... any help would be appreciated

[kbenson]

I'm confused as to whether you have the names and know the format, and they are always something like "video-$NUMBER.mp4", or whether you have a list of files, and just want to iterate through them.

For a known format, where the number is a monotonically increasing integer:

numFiles = 10
for i=0 to numFiles
    filename = "video-"+i.toStr()+".mp4"
    ' do something
end for

For a list of files:

files = ["file1.mp4", "other.mp4", "file23534.mp4"]
for each file in files
    ' file contains filename from files array
    ' do something
end for

Or am I just completely missing your point?

[dynamitemedia]

filename = "video-"+i.toStr()+".mp4"

it was the toStr() i had left out. Thanks!

nope you hit it right on the head, will test it now...

im too busy playing ur new game 😉

[kbenson]

"dynamitemedia" wrote:

filename = "video-"+i.toStr()+".mp4"

it was the toStr() i had left out. Thanks!

There's also the stri() function, so you can do

filename = "video-"+stri(i)+".mp4"

but I prefer the interface methods.

im too busy playing ur new game 😉

🙂

[dynamitemedia]

now i have another question about this...

how could i do this with out knowing how many files there are? and want to get that number dynamically

numFiles = 10

say i want to check this folder for videos or images in this folder tmp:/new/
with image or video names like this:

image-01
image-02

or

video-01
video-02

i know in php i can do a count of files with that name, but how could i do that here? so it would then come back something like this:

filename = "image-"
whatever here to get the count of "filename"  ending up with something like this
count =
numFiles = count

would it need the extension of the file? like .mp4 or .jpg ?

[RokuChris]

roFileSystem::Find() might be a simpler way to accomplish what you're trying to do. The first parameter is the directory you want to search and the second is a regular expression that files must match to be included in the result, so to find all .mp4 or .jpg files in tmp:/new, you might say this...

fs = CreateObject("roFileSystem")
files = fs.Find("tmp:/new/", "\.(mp4|jpg)$")

[dynamitemedia]

thanks chris, i knew there had to be a function to do that.
i am not at home to check, but what if there are multiple .jpg's but i only want the ones with the word
"newImage-" and these all have

01,02 etc on the end

could i use a " * " wildcard?

wildCard = "newImage-*.jpg"

fs = CreateObject("roFileSystem")
files = fs.Find("tmp:/new/", wildCard)

plus i will prob just need to use this for either a image or a video, but not together. but its awesome i know how to do it if i need to later!

[kbenson]

"dynamitemedia" wrote:

could i use a " * " wildcard?

No, but you could use .*
Like this, assuming the files must BEGIN with newImage and end with .jpg.

wildCard = "^newImage-.*\.jpg$"

It uses a regular expression, not a shell expansion. That MUCH too large a topic to cover here. Luckily, there's a plethora of tutorials to get you started online.

[dynamitemedia]

yes that is a whole another can of worms!!

and thanks, that actually makes sense what you added. Yes i wanted that name exactly, just in case other jpg's or even mp4's were still hanging around... didnt want the count wrong

most of these i will do server side, but its good to know what all options i have.

i'll test when i get home if i have any more questions